(2x^3-x^2+7)(2x+3)=

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Solution for (2x^3-x^2+7)(2x+3)= equation: 


Simplifying
(2x3 + -1x2 + 7)(2x + 3) = 0

Reorder the terms:
(7 + -1x2 + 2x3)(2x + 3) = 0

Reorder the terms:
(7 + -1x2 + 2x3)(3 + 2x) = 0

Multiply (7 + -1x2 + 2x3) * (3 + 2x)
(7(3 + 2x) + -1x2 * (3 + 2x) + 2x3 * (3 + 2x)) = 0
((3 * 7 + 2x * 7) + -1x2 * (3 + 2x) + 2x3 * (3 + 2x)) = 0
((21 + 14x) + -1x2 * (3 + 2x) + 2x3 * (3 + 2x)) = 0
(21 + 14x + (3 * -1x2 + 2x * -1x2) + 2x3 * (3 + 2x)) = 0
(21 + 14x + (-3x2 + -2x3) + 2x3 * (3 + 2x)) = 0
(21 + 14x + -3x2 + -2x3 + (3 * 2x3 + 2x * 2x3)) = 0
(21 + 14x + -3x2 + -2x3 + (6x3 + 4x4)) = 0

Combine like terms: -2x3 + 6x3 = 4x3
(21 + 14x + -3x2 + 4x3 + 4x4) = 0

Solving
21 + 14x + -3x2 + 4x3 + 4x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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